Optimal. Leaf size=146 \[ b^2 c^2 \log \left (2-\frac {2}{1-i c x^3}\right ) \left (a+b \tan ^{-1}\left (c x^3\right )\right )-\frac {1}{2} i b c^2 \left (a+b \tan ^{-1}\left (c x^3\right )\right )^2-\frac {1}{6} c^2 \left (a+b \tan ^{-1}\left (c x^3\right )\right )^3-\frac {b c \left (a+b \tan ^{-1}\left (c x^3\right )\right )^2}{2 x^3}-\frac {\left (a+b \tan ^{-1}\left (c x^3\right )\right )^3}{6 x^6}-\frac {1}{2} i b^3 c^2 \text {Li}_2\left (\frac {2}{1-i c x^3}-1\right ) \]
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Rubi [F] time = 1.67, antiderivative size = 0, normalized size of antiderivative = 0.00, number of steps used = 0, number of rules used = 0, integrand size = 0, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.000, Rules used = {} \[ \int \frac {\left (a+b \tan ^{-1}\left (c x^3\right )\right )^3}{x^7} \, dx \]
Verification is Not applicable to the result.
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Rubi steps
\begin {align*} \int \frac {\left (a+b \tan ^{-1}\left (c x^3\right )\right )^3}{x^7} \, dx &=\int \left (\frac {\left (2 a+i b \log \left (1-i c x^3\right )\right )^3}{8 x^7}+\frac {3 i b \left (-2 i a+b \log \left (1-i c x^3\right )\right )^2 \log \left (1+i c x^3\right )}{8 x^7}-\frac {3 i b^2 \left (-2 i a+b \log \left (1-i c x^3\right )\right ) \log ^2\left (1+i c x^3\right )}{8 x^7}+\frac {i b^3 \log ^3\left (1+i c x^3\right )}{8 x^7}\right ) \, dx\\ &=\frac {1}{8} \int \frac {\left (2 a+i b \log \left (1-i c x^3\right )\right )^3}{x^7} \, dx+\frac {1}{8} (3 i b) \int \frac {\left (-2 i a+b \log \left (1-i c x^3\right )\right )^2 \log \left (1+i c x^3\right )}{x^7} \, dx-\frac {1}{8} \left (3 i b^2\right ) \int \frac {\left (-2 i a+b \log \left (1-i c x^3\right )\right ) \log ^2\left (1+i c x^3\right )}{x^7} \, dx+\frac {1}{8} \left (i b^3\right ) \int \frac {\log ^3\left (1+i c x^3\right )}{x^7} \, dx\\ &=\frac {1}{24} \operatorname {Subst}\left (\int \frac {(2 a+i b \log (1-i c x))^3}{x^3} \, dx,x,x^3\right )+\frac {1}{8} (i b) \operatorname {Subst}\left (\int \frac {(-2 i a+b \log (1-i c x))^2 \log (1+i c x)}{x^3} \, dx,x,x^3\right )-\frac {1}{8} \left (i b^2\right ) \operatorname {Subst}\left (\int \frac {(-2 i a+b \log (1-i c x)) \log ^2(1+i c x)}{x^3} \, dx,x,x^3\right )+\frac {1}{24} \left (i b^3\right ) \operatorname {Subst}\left (\int \frac {\log ^3(1+i c x)}{x^3} \, dx,x,x^3\right )\\ &=-\frac {\left (2 a+i b \log \left (1-i c x^3\right )\right )^3}{48 x^6}-\frac {i b^3 \log ^3\left (1+i c x^3\right )}{48 x^6}+\frac {1}{8} (i b) \operatorname {Subst}\left (\int \frac {(-2 i a+b \log (1-i c x))^2 \log (1+i c x)}{x^3} \, dx,x,x^3\right )-\frac {1}{8} \left (i b^2\right ) \operatorname {Subst}\left (\int \frac {(-2 i a+b \log (1-i c x)) \log ^2(1+i c x)}{x^3} \, dx,x,x^3\right )+\frac {1}{16} (b c) \operatorname {Subst}\left (\int \frac {(2 a+i b \log (1-i c x))^2}{x^2 (1-i c x)} \, dx,x,x^3\right )-\frac {1}{16} \left (b^3 c\right ) \operatorname {Subst}\left (\int \frac {\log ^2(1+i c x)}{x^2 (1+i c x)} \, dx,x,x^3\right )\\ &=-\frac {\left (2 a+i b \log \left (1-i c x^3\right )\right )^3}{48 x^6}-\frac {i b^3 \log ^3\left (1+i c x^3\right )}{48 x^6}+\frac {1}{16} (i b) \operatorname {Subst}\left (\int \frac {(2 a+i b \log (x))^2}{x \left (-\frac {i}{c}+\frac {i x}{c}\right )^2} \, dx,x,1-i c x^3\right )+\frac {1}{8} (i b) \operatorname {Subst}\left (\int \frac {(-2 i a+b \log (1-i c x))^2 \log (1+i c x)}{x^3} \, dx,x,x^3\right )-\frac {1}{8} \left (i b^2\right ) \operatorname {Subst}\left (\int \frac {(-2 i a+b \log (1-i c x)) \log ^2(1+i c x)}{x^3} \, dx,x,x^3\right )+\frac {1}{16} \left (i b^3\right ) \operatorname {Subst}\left (\int \frac {\log ^2(x)}{x \left (\frac {i}{c}-\frac {i x}{c}\right )^2} \, dx,x,1+i c x^3\right )\\ &=-\frac {\left (2 a+i b \log \left (1-i c x^3\right )\right )^3}{48 x^6}-\frac {i b^3 \log ^3\left (1+i c x^3\right )}{48 x^6}+\frac {1}{16} (i b) \operatorname {Subst}\left (\int \frac {(2 a+i b \log (x))^2}{\left (-\frac {i}{c}+\frac {i x}{c}\right )^2} \, dx,x,1-i c x^3\right )+\frac {1}{8} (i b) \operatorname {Subst}\left (\int \frac {(-2 i a+b \log (1-i c x))^2 \log (1+i c x)}{x^3} \, dx,x,x^3\right )-\frac {1}{8} \left (i b^2\right ) \operatorname {Subst}\left (\int \frac {(-2 i a+b \log (1-i c x)) \log ^2(1+i c x)}{x^3} \, dx,x,x^3\right )+\frac {1}{16} \left (i b^3\right ) \operatorname {Subst}\left (\int \frac {\log ^2(x)}{\left (\frac {i}{c}-\frac {i x}{c}\right )^2} \, dx,x,1+i c x^3\right )-\frac {1}{16} (b c) \operatorname {Subst}\left (\int \frac {(2 a+i b \log (x))^2}{x \left (-\frac {i}{c}+\frac {i x}{c}\right )} \, dx,x,1-i c x^3\right )+\frac {1}{16} \left (b^3 c\right ) \operatorname {Subst}\left (\int \frac {\log ^2(x)}{x \left (\frac {i}{c}-\frac {i x}{c}\right )} \, dx,x,1+i c x^3\right )\\ &=-\frac {b c \left (1-i c x^3\right ) \left (2 a+i b \log \left (1-i c x^3\right )\right )^2}{16 x^3}-\frac {\left (2 a+i b \log \left (1-i c x^3\right )\right )^3}{48 x^6}+\frac {b^3 c \left (1+i c x^3\right ) \log ^2\left (1+i c x^3\right )}{16 x^3}-\frac {i b^3 \log ^3\left (1+i c x^3\right )}{48 x^6}+\frac {1}{8} (i b) \operatorname {Subst}\left (\int \frac {(-2 i a+b \log (1-i c x))^2 \log (1+i c x)}{x^3} \, dx,x,x^3\right )-\frac {1}{8} \left (i b^2\right ) \operatorname {Subst}\left (\int \frac {(-2 i a+b \log (1-i c x)) \log ^2(1+i c x)}{x^3} \, dx,x,x^3\right )-\frac {1}{16} (b c) \operatorname {Subst}\left (\int \frac {(2 a+i b \log (x))^2}{-\frac {i}{c}+\frac {i x}{c}} \, dx,x,1-i c x^3\right )+\frac {1}{8} \left (i b^2 c\right ) \operatorname {Subst}\left (\int \frac {2 a+i b \log (x)}{-\frac {i}{c}+\frac {i x}{c}} \, dx,x,1-i c x^3\right )+\frac {1}{16} \left (b^3 c\right ) \operatorname {Subst}\left (\int \frac {\log ^2(x)}{\frac {i}{c}-\frac {i x}{c}} \, dx,x,1+i c x^3\right )-\frac {1}{8} \left (b^3 c\right ) \operatorname {Subst}\left (\int \frac {\log (x)}{\frac {i}{c}-\frac {i x}{c}} \, dx,x,1+i c x^3\right )-\frac {1}{16} \left (i b c^2\right ) \operatorname {Subst}\left (\int \frac {(2 a+i b \log (x))^2}{x} \, dx,x,1-i c x^3\right )-\frac {1}{16} \left (i b^3 c^2\right ) \operatorname {Subst}\left (\int \frac {\log ^2(x)}{x} \, dx,x,1+i c x^3\right )\\ &=\frac {3}{4} a b^2 c^2 \log (x)-\frac {b c \left (1-i c x^3\right ) \left (2 a+i b \log \left (1-i c x^3\right )\right )^2}{16 x^3}+\frac {1}{16} i b c^2 \log \left (i c x^3\right ) \left (2 a+i b \log \left (1-i c x^3\right )\right )^2-\frac {\left (2 a+i b \log \left (1-i c x^3\right )\right )^3}{48 x^6}+\frac {b^3 c \left (1+i c x^3\right ) \log ^2\left (1+i c x^3\right )}{16 x^3}+\frac {1}{16} i b^3 c^2 \log \left (-i c x^3\right ) \log ^2\left (1+i c x^3\right )-\frac {i b^3 \log ^3\left (1+i c x^3\right )}{48 x^6}+\frac {1}{8} i b^3 c^2 \text {Li}_2\left (-i c x^3\right )+\frac {1}{8} (i b) \operatorname {Subst}\left (\int \frac {(-2 i a+b \log (1-i c x))^2 \log (1+i c x)}{x^3} \, dx,x,x^3\right )-\frac {1}{8} \left (i b^2\right ) \operatorname {Subst}\left (\int \frac {(-2 i a+b \log (1-i c x)) \log ^2(1+i c x)}{x^3} \, dx,x,x^3\right )-\frac {1}{8} \left (b^3 c\right ) \operatorname {Subst}\left (\int \frac {\log (x)}{-\frac {i}{c}+\frac {i x}{c}} \, dx,x,1-i c x^3\right )-\frac {1}{16} c^2 \operatorname {Subst}\left (\int x^2 \, dx,x,2 a+i b \log \left (1-i c x^3\right )\right )+\frac {1}{8} \left (b^2 c^2\right ) \operatorname {Subst}\left (\int \frac {\log (1-x) (2 a+i b \log (x))}{x} \, dx,x,1-i c x^3\right )-\frac {1}{16} \left (i b^3 c^2\right ) \operatorname {Subst}\left (\int x^2 \, dx,x,\log \left (1+i c x^3\right )\right )-\frac {1}{8} \left (i b^3 c^2\right ) \operatorname {Subst}\left (\int \frac {\log (1-x) \log (x)}{x} \, dx,x,1+i c x^3\right )\\ &=\frac {3}{4} a b^2 c^2 \log (x)-\frac {b c \left (1-i c x^3\right ) \left (2 a+i b \log \left (1-i c x^3\right )\right )^2}{16 x^3}+\frac {1}{16} i b c^2 \log \left (i c x^3\right ) \left (2 a+i b \log \left (1-i c x^3\right )\right )^2-\frac {1}{48} c^2 \left (2 a+i b \log \left (1-i c x^3\right )\right )^3-\frac {\left (2 a+i b \log \left (1-i c x^3\right )\right )^3}{48 x^6}+\frac {b^3 c \left (1+i c x^3\right ) \log ^2\left (1+i c x^3\right )}{16 x^3}+\frac {1}{16} i b^3 c^2 \log \left (-i c x^3\right ) \log ^2\left (1+i c x^3\right )-\frac {1}{48} i b^3 c^2 \log ^3\left (1+i c x^3\right )-\frac {i b^3 \log ^3\left (1+i c x^3\right )}{48 x^6}+\frac {1}{8} i b^3 c^2 \text {Li}_2\left (-i c x^3\right )-\frac {1}{8} i b^3 c^2 \text {Li}_2\left (i c x^3\right )-\frac {1}{8} b^2 c^2 \left (2 a+i b \log \left (1-i c x^3\right )\right ) \text {Li}_2\left (1-i c x^3\right )+\frac {1}{8} i b^3 c^2 \log \left (1+i c x^3\right ) \text {Li}_2\left (1+i c x^3\right )+\frac {1}{8} (i b) \operatorname {Subst}\left (\int \frac {(-2 i a+b \log (1-i c x))^2 \log (1+i c x)}{x^3} \, dx,x,x^3\right )-\frac {1}{8} \left (i b^2\right ) \operatorname {Subst}\left (\int \frac {(-2 i a+b \log (1-i c x)) \log ^2(1+i c x)}{x^3} \, dx,x,x^3\right )+\frac {1}{8} \left (i b^3 c^2\right ) \operatorname {Subst}\left (\int \frac {\text {Li}_2(x)}{x} \, dx,x,1-i c x^3\right )-\frac {1}{8} \left (i b^3 c^2\right ) \operatorname {Subst}\left (\int \frac {\text {Li}_2(x)}{x} \, dx,x,1+i c x^3\right )\\ &=\frac {3}{4} a b^2 c^2 \log (x)-\frac {b c \left (1-i c x^3\right ) \left (2 a+i b \log \left (1-i c x^3\right )\right )^2}{16 x^3}+\frac {1}{16} i b c^2 \log \left (i c x^3\right ) \left (2 a+i b \log \left (1-i c x^3\right )\right )^2-\frac {1}{48} c^2 \left (2 a+i b \log \left (1-i c x^3\right )\right )^3-\frac {\left (2 a+i b \log \left (1-i c x^3\right )\right )^3}{48 x^6}+\frac {b^3 c \left (1+i c x^3\right ) \log ^2\left (1+i c x^3\right )}{16 x^3}+\frac {1}{16} i b^3 c^2 \log \left (-i c x^3\right ) \log ^2\left (1+i c x^3\right )-\frac {1}{48} i b^3 c^2 \log ^3\left (1+i c x^3\right )-\frac {i b^3 \log ^3\left (1+i c x^3\right )}{48 x^6}+\frac {1}{8} i b^3 c^2 \text {Li}_2\left (-i c x^3\right )-\frac {1}{8} i b^3 c^2 \text {Li}_2\left (i c x^3\right )-\frac {1}{8} b^2 c^2 \left (2 a+i b \log \left (1-i c x^3\right )\right ) \text {Li}_2\left (1-i c x^3\right )+\frac {1}{8} i b^3 c^2 \log \left (1+i c x^3\right ) \text {Li}_2\left (1+i c x^3\right )+\frac {1}{8} i b^3 c^2 \text {Li}_3\left (1-i c x^3\right )-\frac {1}{8} i b^3 c^2 \text {Li}_3\left (1+i c x^3\right )+\frac {1}{8} (i b) \operatorname {Subst}\left (\int \frac {(-2 i a+b \log (1-i c x))^2 \log (1+i c x)}{x^3} \, dx,x,x^3\right )-\frac {1}{8} \left (i b^2\right ) \operatorname {Subst}\left (\int \frac {(-2 i a+b \log (1-i c x)) \log ^2(1+i c x)}{x^3} \, dx,x,x^3\right )\\ \end {align*}
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Mathematica [A] time = 0.35, size = 196, normalized size = 1.34 \[ -\frac {a \left (a \left (a+3 b c x^3\right )-6 b^2 c^2 x^6 \log \left (\frac {c x^3}{\sqrt {c^2 x^6+1}}\right )\right )+3 b^2 \tan ^{-1}\left (c x^3\right )^2 \left (a c^2 x^6+a+b c x^3 \left (1+i c x^3\right )\right )+3 b \tan ^{-1}\left (c x^3\right ) \left (a \left (a c^2 x^6+a+2 b c x^3\right )-2 b^2 c^2 x^6 \log \left (1-e^{2 i \tan ^{-1}\left (c x^3\right )}\right )\right )+3 i b^3 c^2 x^6 \text {Li}_2\left (e^{2 i \tan ^{-1}\left (c x^3\right )}\right )+b^3 \left (c^2 x^6+1\right ) \tan ^{-1}\left (c x^3\right )^3}{6 x^6} \]
Warning: Unable to verify antiderivative.
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fricas [F] time = 0.45, size = 0, normalized size = 0.00 \[ {\rm integral}\left (\frac {b^{3} \arctan \left (c x^{3}\right )^{3} + 3 \, a b^{2} \arctan \left (c x^{3}\right )^{2} + 3 \, a^{2} b \arctan \left (c x^{3}\right ) + a^{3}}{x^{7}}, x\right ) \]
Verification of antiderivative is not currently implemented for this CAS.
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giac [F] time = 0.00, size = 0, normalized size = 0.00 \[ \int \frac {{\left (b \arctan \left (c x^{3}\right ) + a\right )}^{3}}{x^{7}}\,{d x} \]
Verification of antiderivative is not currently implemented for this CAS.
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maple [F] time = 0.88, size = 0, normalized size = 0.00 \[ \int \frac {\left (a +b \arctan \left (c \,x^{3}\right )\right )^{3}}{x^{7}}\, dx \]
Verification of antiderivative is not currently implemented for this CAS.
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maxima [F] time = 0.00, size = 0, normalized size = 0.00 \[ -\frac {1}{2} \, {\left ({\left (c \arctan \left (c x^{3}\right ) + \frac {1}{x^{3}}\right )} c + \frac {\arctan \left (c x^{3}\right )}{x^{6}}\right )} a^{2} b + \frac {1}{2} \, {\left ({\left (\arctan \left (c x^{3}\right )^{2} - \log \left (c^{2} x^{6} + 1\right ) + 6 \, \log \relax (x)\right )} c^{2} - 2 \, {\left (c \arctan \left (c x^{3}\right ) + \frac {1}{x^{3}}\right )} c \arctan \left (c x^{3}\right )\right )} a b^{2} - \frac {a b^{2} \arctan \left (c x^{3}\right )^{2}}{2 \, x^{6}} + \frac {\frac {3}{8} \, {\left (8 \, x^{6} \int -\frac {84 \, c^{2} x^{6} \arctan \left (c x^{3}\right ) \log \left (c^{2} x^{6} + 1\right ) - 180 \, c x^{3} \arctan \left (c x^{3}\right )^{2} - 392 \, {\left (c^{2} x^{6} + 1\right )} \arctan \left (c x^{3}\right )^{3} + 21 \, {\left (c x^{3} - 2 \, {\left (c^{2} x^{6} + 1\right )} \arctan \left (c x^{3}\right )\right )} \log \left (c^{2} x^{6} + 1\right )^{2}}{8 \, {\left (c^{2} x^{13} + x^{7}\right )}}\,{d x} - 20 \, \arctan \left (c x^{3}\right )^{3} + 7 \, \arctan \left (c x^{3}\right ) \log \left (c^{2} x^{6} + 1\right )^{2}\right )} b^{3}}{192 \, x^{6}} - \frac {a^{3}}{6 \, x^{6}} \]
Verification of antiderivative is not currently implemented for this CAS.
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mupad [F] time = 0.00, size = -1, normalized size = -0.01 \[ \int \frac {{\left (a+b\,\mathrm {atan}\left (c\,x^3\right )\right )}^3}{x^7} \,d x \]
Verification of antiderivative is not currently implemented for this CAS.
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sympy [F] time = 0.00, size = 0, normalized size = 0.00 \[ \int \frac {\left (a + b \operatorname {atan}{\left (c x^{3} \right )}\right )^{3}}{x^{7}}\, dx \]
Verification of antiderivative is not currently implemented for this CAS.
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